Question

if unbiased coin is tossed twice, the probability of obtaining at least one tail is

Answer 1

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Answer 2

P(E) = $\dfrac{3}{4}$

Step-by-step explanation:

When unbiased coin is tossed twice.

The all possible outcomes are:

(H, H), (H, T), (T, H) and (T, T).

Total number of possible outcomes = 4

Let E be the getting at least one tail.

The favorable outcomes are:

(H, T), (T, H) and (T, T).

Number of favorable outcomes = 3

∴ Probability, P(E) = $\dfrac{Number of favorable outcomes}{Total number of possible outcomes}$

P(E) = $\dfrac{3}{4}$

Thus, P(E) = $\dfrac{3}{4}$