Question

if uncertainity in x of electron is 0.33 pm calculate uncertainity in velocity.​

Answer 1

Answer:

∆v= 1.75673×10^8 m/s

Explanation:

∆x= 0.33pm= 0.33×10^-12m

∆v=h/4πm∆x

∆v= 6.626×10^-34/4×3.14×9.1×10^-31×0.33×10^-12

∆v= 1.75673×10^8 m/s