If under a correspondence, the hypotenuse and one side of a right-angled triangle are respectively equal to the hypotenuse and one side of another right-angled triangle, then the triangles are congruent. Reason (R): ΔABC, AC=8cm BC=3cm ∠B= 90^0 ΔPQR, PR=8cm QR=3cm ∠Q= 90^0 Then ΔABC ≅ ΔPQR
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ΔABC, AC=8cm BC=3cm ∠B= 90^0 ΔPQR, PR=8cm QR=3cm ∠Q= 90^0 Then ΔABC ≅ ΔPQR
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