Question

if under root 3 tan x -1=0,then sin x =................

Answer 1

Answer:

√3tanx -1=0

√3tanx=1

(√3tanx )²=1²

tanx=1/3

by pythagorus theorum,

h²=p²+b²

h²=1²+3²

h=√10

now,

sinx=p/h = 1/√10