Question

If under root of x/y+underofy/x=10/3 find xy

Answer 1

root of x÷y+root y÷x=10÷3 . squaring on both sides we will get x^2+y^2÷xy+2=100÷9 so x^2+y^2÷xy=82÷9 by comparison x^2+y^2=82 and xy=9 so we will get xy=9