Question

if underroot 1+27/169 = 1+x/13 , find the value of x

Answer 1

Hey mate!!!

$<b >Here is your answer :</b >$

Given,
$sqrt(1 + \frac{27}{169}) = 1 + \frac{x} {13}$
=>$1 + \frac{27}{169} = (1 + \frac{x} {13})^2$
=>$1 + \frac{27}{169} = 1 + \frac{2x}{13} + \frac{x^2}{169}$
=>$\frac{27}{169} = \frac{26x + x^2}{169}$
=>$x^2 + 26x = 27$, because the bases are equal.
=>$x^2 + 26x - 27 = 0$
By middle term splitting factorisation,
=>$x^2 + (27 - 1)x - 27 = 0$
=>$x^2 + 27x - x - 27 = 0$
=>$x(x + 27) - 1(x + 27) = 0$
=>$(x + 27)(x - 1) = 0$
=>$<big><b><u> x = 1 or (- 27) </b></u>$

$<b><marquee >I hope it helps you #need more brainliests marks$