if unequal side of an isosceles triangle is 6cm and it's perimeter is 24 cm. find its area by using heron's formula.
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Answered by
71
Let the equal side be x
So 6+x+x=24
2x=18
x=9
s=24/2=12
area=√12(12-6)(12-9)(12-9)
=√12×6×3×3
=18√2 sq.cm
So 6+x+x=24
2x=18
x=9
s=24/2=12
area=√12(12-6)(12-9)(12-9)
=√12×6×3×3
=18√2 sq.cm
Answered by
25
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