Physics, asked by mira21, 1 year ago

If unit of mass is assumed as 10 kg, unit of length
20 m, and unit of time as 50 s. Then the value of
1 newton of force in new system of units is
(1) 10
(2) 12.5
(3) 25
(4) 20​

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Answers

Answered by VineetaGara
0

Answer:

The answer is option (2) 12.5

Explanation:

Let assume that 1 N is x unit or we can say 1N=x kg.m.s^-2

Let for the first system mass=M1, length=L1 and time=T1

M1=1kg, L1=1m and T1=1sec

Let for the second system mass=M2, length=L2 and time=T2

Given, M2=10kg, L2=20m, T2=50s

Then 1 newton of force in new system should be

[M1/M2]X[L1/L2]X[T1/T2]^-2

=> [1/10]X[1/20]X[1/50]^-2

=> 1/10 x 1/20 x 2500\

=> 12.5 (Option 2)

Answered by manasamanasareddy16
0

Explanation:

is this byjus question paper?

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