Question

if unit of mass is assumed as 10kg unit of length is 20m and unit of time is 50s.Then the value of 1N of force in new system of units is​

Answer 1

Answer ⇒  Value of 1 N in this system of units is 12.5 times newton in olden units.

Explanation ⇒   ∴ In New system,

M₂ = 10 kg, L₂ = 20 M and T₂ = 50 s.

In Old system,

M₁ = 1 kg, L₁ = 1 m and T₁ = 1 seconds.

∴ M₁/M₂ = 1/10 , L₁/L₂ = 1/20 and T₁/T₂ = 1/50

Now, In Olden system, 1 N = 1kgm/s².

Using the formula,

$n_2 = n_1 [\frac{M_1}{M_2}][\frac{L_1}{L_2}][\frac{T_1}{T_2}]^-^2$

In this formula, n₁ represents the S.I. Units whereas, n₂ represents new unit.

∴ n₂ = 1 × 1/10 × 1/20 × 2500

∴ n₂ = 2500/200

∴ n₂ = 12.5 units.

∴ Value of 1 N in this system of units is 12.5 times newton in olden units.

Hope it helps.

Answer 2

Answer ⇒ Value of 1 N in this system of units is 12.5 times newton in olden units.

Explanation ⇒ ∴ In New system,

M₂ = 10 kg, L₂ = 20 M and T₂ = 50 s.

In Old system,

M₁ = 1 kg, L₁ = 1 m and T₁ = 1 seconds.

∴ M₁/M₂ = 1/10 , L₁/L₂ = 1/20 and T₁/T₂ = 1/50

Now, In Olden system, 1 N = 1kgm/s².

Using the formula,

In this formula, n₁ represents the S.I. Units whereas, n₂ represents new unit.

∴ n₂ = 1 × 1/10 × 1/20 × 2500

∴ n₂ = 2500/200

∴ n₂ = 12.5 units.

∴ Value of 1 N in this system of units is 12.5 times newton in olden units.

Hope it helps.