Question

If unit of time is taken as 10s unit of mass 5kg unit of length 20m then convert 1j in new unit of energy
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Answer 1

Answer:

1/20

Explanation:

Dimensions of Joule : $[M^{1} L^{2}T^{-2}]$

now new unit is denoted by subscript 2 and original by 1

$Joule_{2}$ = $[(5M)^{1} (20L)^{2} (10T)^{-2}]$  ......eq1

$Joule_{1}$ = $[M^{1} L^{2}T^{-2}]$   ....... eq2

dividing the two equations we get

$\frac{Joule_{2}}{Joule_{1}}$ = $(\frac{5}{1} )^{1} *(\frac{20}{1} )^{2}*(\frac{10}{1} )^{-2}$

by solving for $Joule_{2}$

we get $Joule_{2}$  = 20$Joule_{1}$

and 1$Joule_{1}$ = $Joule_{2}$$\frac{1}{20}$