if ur a genius then u will ans this 7,8,9 question
Answers
Que:-7 ,Picture -1
Garden is shown in green colour and path is shown in red colour ,
Now,
PQ = 125 m
PS = 60 m
Area of PQRS = 125 × 60
= 7500 m²
AD = 125 + 4 + 4 = 133 m
AB = 60 + 4 + 4 = 68 m
Area of ABCD = 133 × 68
= 9044 m²
Hence,
Area of path = 9044 - 7500
= 1544 m²
Cost of paving 1 m² = R.s. 120
Cost of paving 1544 m² = 1544 × 120 = R.s. 1,85,280
Qus:8 Picture : 2
PQ = 5 m
PS = 7.5 m
Area of PQRS = 5 × 7.5
= 37.5 m²
AD = 7.5+ 1.25 + 1.25 = 10 m
AB = 5 + 1.25 + 1.25 = 7.5 m
Area of ABCD =7.5 × 10
= 75 m²
Hence,
Area of Verndah = 75 - 37.5
= 37.5 m²
Cost of cementing of 1 m² = R.s. 15
Cost of paving 1544 m² = 37.5 × 15 = R.s. 562.5
Qus:9 Picture : 3
Area of ABCD (garden)= 500 × 250
= 125000 m²
Area of PQRS = 250 × 8
= 2000 m²
Area of FGHI = 500 × 8
= 4000
Area of orange field = 8 ×8
= 64 m²
Now, if we add area of FGHI and PQRS , we will have two times area of orange field ,
Hence,
Area of crossroad = 4000+2000 - 64
= 5936 m²
Area of garden excluding crossroad = 125000 - 5936
= 119064 m²
