Math, asked by Hriteeka8903, 1 year ago

If urn a consists of 6 red and 4 black balls and urn b contains 4red and 6black balls,one ball is drawn at random from urn a and placed in urn

b.Then one ball is drawn at random from urn b and placed in urn

a.If one ball is drawn at random from urn a, the probability that is found to be red,is

Answers

Answered by Chaitali23
1

Answer:

5

Steps:

In urn A it has 6 red and 4 black balls.

In urn B it has 4 red and 6 black balls.

Now from urn A one red ball is removed & placed in urn B.

Then next from urn B one red ball is removed & placed in again urn A.

Next one red ball is removed out. The the total ball - ball removed from urn A.

=6-1

=5

Hope it helps u.

Actually i don't know that from which class is this sum.

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