If urn a consists of 6 red and 4 black balls and urn b contains 4red and 6black balls,one ball is drawn at random from urn a and placed in urn
b.Then one ball is drawn at random from urn b and placed in urn
a.If one ball is drawn at random from urn a, the probability that is found to be red,is
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1
Answer:
5
Steps:
In urn A it has 6 red and 4 black balls.
In urn B it has 4 red and 6 black balls.
Now from urn A one red ball is removed & placed in urn B.
Then next from urn B one red ball is removed & placed in again urn A.
Next one red ball is removed out. The the total ball - ball removed from urn A.
=6-1
=5
Hope it helps u.
Actually i don't know that from which class is this sum.
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