If v=(10+-0.2)volt and I=(5+-0.1) amper
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Answer:
2+-0.04
Explanation:
it is given using the law of error analysis.
we know that r=v/i.
therefore now, using error analysis to get the max. possible error in r.
(delta r)/r=(delta v)/v+(delta i)/i
by error analysis formula .
so we get ,
(delta r)/r= 0.2/10+0.1/5(see here the sign of the error is always positive i.e, all the errors will be added in the same way of they are in division).
(delta r)/r=0.04.
And by r=v/i.
we get r=10/5=2ohm.
Therefore the ans is: r=2+-0.04
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