If v=10 power 4 and q=100micro farad amoit of work is??
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Answered by
0
Explanation:
Given , charge =q=8×10
−18
C and Capacitance =C=100μF
Here the work done is the energy stored in the capacitor. i.e,
W=
C
q
2
=
100×10
−6
(8×10
−18
)
2
=32×10
−32
J
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