Question

If v=10 power 4 and q=100micro farad amoit of work is??

Answer 1

Explanation:

Given , charge =q=8×10

−18

C and Capacitance =C=100μF

Here the work done is the energy stored in the capacitor. i.e,

W=

C

q

2

=

100×10

−6

(8×10

−18

)

2

=32×10

−32

J