Physics, asked by soumadityass2004, 4 months ago


If v= 2t, R = 9 m. Find Centripetal acceleration , Tangential acceleration ,Net acceleration at t= 3 sec.​

Answers

Answered by sakthiatl1
4

Answer:

centripetal acceleration = 4 m/s²

tangential acceleration = 2 m /s²

Explanation:

centripetal acceleration  ac = v² / r

    = (2t)² / r = 4t² /r = 4 x 3² / 9 = 4 m/s²

tangential acceleration at = dv/dt = d/dt ( 2t) = 2 m/s²

Net acceleration \sqrt{ac^{2} +at2 = root ( 16 +4 ) = root ( 20) = 4.47 m/s²

 

Answered by anuragb1004
0

Answer:

centripetal acceleration = 4 m/s²

tangential acceleration = 2 m /s²

Explanation:

centripetal acceleration ac = v² / r

= (2t)² / r = 4t² /r = 4 x 3² / 9 = 4 m/s²

tangential acceleration at = dv/dt = d/dt ( 2t) = 2 m/s²

Net acceleration $$\sqrt{ac^{2} +at2$$ = root ( 16 +4 ) = root ( 20) = 4.47 m/s²

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