If v= 2t, R = 9 m. Find Centripetal acceleration , Tangential acceleration ,Net acceleration at t= 3 sec.
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Answered by
4
Answer:
centripetal acceleration = 4 m/s²
tangential acceleration = 2 m /s²
Explanation:
centripetal acceleration ac = v² / r
= (2t)² / r = 4t² /r = 4 x 3² / 9 = 4 m/s²
tangential acceleration at = dv/dt = d/dt ( 2t) = 2 m/s²
Net acceleration = root ( 16 +4 ) = root ( 20) = 4.47 m/s²
Answered by
0
Answer:
centripetal acceleration = 4 m/s²
tangential acceleration = 2 m /s²
Explanation:
centripetal acceleration ac = v² / r
= (2t)² / r = 4t² /r = 4 x 3² / 9 = 4 m/s²
tangential acceleration at = dv/dt = d/dt ( 2t) = 2 m/s²
Net acceleration $$\sqrt{ac^{2} +at2$$ = root ( 16 +4 ) = root ( 20) = 4.47 m/s²
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