if V=4/3π r³,find 1)the value of V when r=5 2)the value of r when V=133 1/7 (take π 22/7)
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Step-by-step explanation:
V = (4 ÷ 3) × (22 ÷ 7) × 5³
V = (4 ÷ 3) × (22 ÷ 7) × 125
V = 523.8
133 1/7 = (4 ÷ 3) × (22 ÷ 7) × r³
r³ = (133 1/7) ÷ [(4 ÷ 3) × (22 ÷ 7)]
r³ = 31.77
r = 31.77⅓
r = 3.17
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1)V= 3.39 ×10`³ ( note:- power is in negative)
2) r= 6.79
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