Question

if v=at/bx-t2. find dimensions of a. here v is velocity t is time. x is lenght. a ,b is unknown quantities. find M1 L1 T °​

Answer 1

Answer:

GIVEN : - v = At / ( Bx - t^2 )

Therefore , For [ A ] : -

v × ( Bt - t^2 ) = At => A = v/t × ( Bx - t^2 )

i.e ,

Since , Bx - t^2 => [ Bx ] = [ t^2 ]

=> [ B ] = [ t^2 ] / [ x ]

=> [ B ] = sec. × sec. / m = Sec. ^2 / m

& ,

Since , A = v/t × ( Bx - t^2 )

[ A ] = m / sec.^2 × ( sec. ^2 / m × m - sec. ^2 )

[ A ] = m / sec. ^2 × sec. ^2

[ A ] = m => [ M ^0 L ^1 T ^0 ] i.e ( 3 )

Answer 2

Explanation:

$v= \frac{At}{Bx- {t}^{2} } \\ \\ [ {M}^{0} {L}^{1} {T}^{-1} ]= \frac{A[T]}{[ {T}^{2}] } \\ \\ A=[ {M}^{0} {L}^{1} {T}^{-1} ][T] \\ \\ \boxed{A=[ {M}^{0} {L}^{1} {T}^{0} ]}\\ \\ \blue{ \rightarrow (3) \: is \: correct}\\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$