Question

If v is proportional to 2 under root x then find out acceleration when velocity is zero

Answer 1

Given relation between velocity (v) and displacement (x) is

v=a√x

⇒dxdt=a√x

⇒dx√x=adt

⇒∫dx√x=a∫dt

⇒x−12+1−12+1=at+c

Since at t=0 x=0

we get c=0

So 2√x=at

⇒4x=a2t2

⇒x=14a2⋅t2

Differentiating w r to t we get

v=dxdt=14a2(2t2−1)

⇒v=12(a2t)

Answer 2

Explanation:

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