if v is the veelocity of a particle moving on a straight lineas a function of time the given as v = 5-t m/s then the distance covered by the particle in first10 s is
e) 15 m
(3) 25 m
(4) 50 m
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Answer:
V = 5 - t
Integration of velocity gives displacement
= 5t - t^2/2
put value of t = 10
= 50 - 100/2
= 50 -50 = 0
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