if V is the volume and S is the surface area of cuboid with dimensions a*b*c,prove that2/S(1/a+1/b+1/c)=1/V
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Answer:
Step-by-step explanation:
abc=V
ab=V/c........1
bc=V/a........2
ac= V/b........3
S=2(ab+bc+ac)
S/2=ab+bc+ac
From 1,2,3
S/2=V/c+V/a+V/b
S/2=V(1/a+1/b+1/c)
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