Question

IF V is the volume of a cuboid of dimensions a, b, c and S is its surface
area then prove that 1/v =2/s(1/a+1/b+1/c)​ plz answer it fast

Answer 1

Hi mate here is the answer:-✍️✍️

Given,

V = volume of cuboid

S = surface area of cuboid

= a,b,c = dimensions of cuboid

So,

S =2(ab+bc+ca)

V=abc

s/v=[2(ab+bc+ca)]/abc=2[(ab/abc)+(bc/abc)+(ca/abc)]

=2(1/a+1/b+1/c)

1/v=2/s(1/a+1/b+1/c)

proved....

Hope it helps you ❣️☑️☑️☑️