Question

If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that 1/V = 2/S(1/a+1/b+1/c).

Answer 1

Step-by-step explanation:

length = a

breadth =b

height = c

volume = lxbxh

sa=s=2(lb+bh+hb)

now,

2/s(1/l+1/b+1/h)=2/2(lb+bh+hl)x[(bh+lh+lb)/lbh]

=1/lbh

=1/v