If V is the volume of a cuboid of dimensions a,b,c and S is the surface area then prove that 1/V=2/S[1/a+1/b+1/c].
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v=a×b×c. and. s=2(ab+bc+ca)
1/abc=2/2(ab+bc+ca)[1/a+1/b+1/c]
=1/ab+bc+ca[bc+ac+ba/abc]
=1/abc
1/abc=2/2(ab+bc+ca)[1/a+1/b+1/c]
=1/ab+bc+ca[bc+ac+ba/abc]
=1/abc
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