if V is the volume of a cuboid of dimensions X Y Z and A is the surface area then A/V
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Given, dimensions of a cuboid are x, y and z.
Now, volume of cube = lbh = xyz
and surface area of cuboid = 2(lb + bh + hl) = 2(xy + yz + zx)
Therefore,A/V=2(lb+BH+hl)/xyz
=2(1/x+1/y+1/z)
Now, volume of cube = lbh = xyz
and surface area of cuboid = 2(lb + bh + hl) = 2(xy + yz + zx)
Therefore,A/V=2(lb+BH+hl)/xyz
=2(1/x+1/y+1/z)
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