if V is the volume of cone of radius R and v one is the volume of cone when the radius is doubled then
a)v=4v1 b) v=2v1 c)v1=2v d)v1=4v
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Answer:
let the Height of the cone=h am
Radius of the cone=r cm
Then volume of the cone=
3
1
πr
2
h
If the height and radius are double then
Height=2h
Radius=2r
Then new volume=
3
1
π(2r)
2
×2h
⇒
3
1
π×4r×2h=8×
3
1
πr
2
h
Hence it is 8 times of the old volume
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