Question

If 'V' is the volume of cuboid dimension a,b,c and s is its surface area then prove that

1/V=2/s [ 1/a + 1/b + 1/c ]

Answer 1

Here is ur answer friend

Answer 2

Answer:

Given dimensions of cuboid are a, b and c.

Therefore, volume of cuboid, V = abc  → (1)

Surface area of cuboid, S = 2(ab + bc + ca)  → (2)

Now divide (2) with (1), we get

S/V = 2(ab+bc+ca)/abc

      = 2[ab/abc+bc/abc+ca/abc]

Therefore, 1/V = 2/S[1/c+1/a+1/b]

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Step-by-step explanation: