Question

If 'v' is the volume of the cuboid having dimensions a×b×c and 's' is surface area 1÷v=2÷s×[1÷a+1÷b+1÷c]

Answer 1

$abc = v.......eq1 \\ s = 2(ab + bc + ca).......eq2 \\ ab = v \div c \\ bc = v \div a \\ ca = v \div b \\ 2 v\div s(1 \div a + 1 \div b + 1 \div c) = 1 \\ 2 \div s(1 \div a + 1 \div b + 1 \div c) = 1 \div v$