Question

If V volt is the stopping potential required for photo electrons and eV is the work function of metal then the energy of incident photon during photo electric effect is?​

Answer 1

Given:

V volt is the stopping potential required for photo electrons and eV is the work function of metal.

To find:

Energy of the incident photons.

Calculation:

Stopping potential = V , so the maximum kinetic energy of the electrons will be ;

$\rm{KE_{max} = eV }$

Now , applying Einstein's Photo-Electric Effect Equation:

$\rm{KE_{max} = E - work \: function}$

$\rm{ = > KE_{max} =E - eV }$

$\rm{ = >eV =E - eV }$

$\rm{ = >E = 2eV }$

So, final answer is:

$\boxed{ \large{ \sf{Energy \: of \: photons = 2eV }}}$

Answer 2

Answer:

Explanation:

When a photon (Y) strikes an electron (E), it knocks it loose and creates a photoelectron. The photoelectric effect refers to what happens when electrons are emitted from a material that has absorbed electromagnetic radiation.