If v=x^2-5x+4 find the acceleration of the particle when velocity of the particle is zero
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v=x^2-5x+4
dv/dx=2x-5
the derivative of velocity is acceleration
so as we know that
v=0
therefore,
acceleration =2x-5
a=5/2
dv/dx=2x-5
the derivative of velocity is acceleration
so as we know that
v=0
therefore,
acceleration =2x-5
a=5/2
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