Math, asked by Amil9659, 1 day ago

If v = √(x²+y²+z²) then show that d²v/dx² + d²v/dy² + d²v/dz² = 0

Answers

Answered by anbukodij

0

Answer:

v"of x=0

v"of y=0

v"ofz=0

adding these answer is 0+0+0=0

hence proved

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