If V20, V15,V5 are the volumes occupied
by an ideal gas at
20°C, 15°C and 5°C then the correct
relation is
(A) V20 = V15 +
V:
273
(B) V20 = V15 +
5V5
273
5V.
(C) V20 = V15 +
273
(D) V20
V15 +
VO
273
Answers
Answered by
0
Answer:
Correct option is
C
2
γ+1
Fro an adiabatic process Tv
r−1
=constant, we know that average time of collision between molecules
τ=
nπ
2
V
rms
d
2
1
where n= no, of molecules per unit volume
V
rms
=rms velocity of molecules
As n∝
V
1
and V
rms
∝
t
τ∝
T
V
Thus we can write:
n=k
1
v
−1
and V
rms
=K
2
T
1/2
where k
1
and k−2 are constant
for adiabatic process TV
r−1
= constant
Thus we can write
τ∝VT
−1/2
∝V(v
1−r
)
−1/2
or τ∝V
2
r+1
Average time between collision =
V
rms
means free path
t=
M
3RT
πd
2
N/V
1
;t=
T
CV
where C=
πd
2
B
3R
M
⇒T∝
t
2
V
2
For adiabatic
TV
γ−1
=k
t
2
V
2
V
γ−1
=k
t
2
V
γ−1
=k, t∝
2
γ+1
so q=
2
γ+1
Explanation:
hope it helps u
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