Question

If V20, V15,V5 are the volumes occupied
by an ideal gas at
20°C, 15°C and 5°C then the correct
relation is
(A) V20 = V15 +
V:
273
(B) V20 = V15 +
5V5
273
5V.
(C) V20 = V15 +
273
(D) V20
V15 +
VO
273​

Answer 1

Answer:

Correct option is

C

2

γ+1

Fro an adiabatic process Tv

r−1

=constant, we know that average time of collision between molecules

τ=

nπ

2

V

rms

d

2

1

where n= no, of molecules per unit volume

V

rms

=rms velocity of molecules

As n∝

V

1

and V

rms

∝

t

τ∝

T

V

Thus we can write:

n=k

1

v

−1

and V

rms

=K

2

T

1/2

where k

1

and k−2 are constant

for adiabatic process TV

r−1

= constant

Thus we can write

τ∝VT

−1/2

∝V(v

1−r

)

−1/2

or τ∝V

2

r+1

Average time between collision =

V

rms

means free path

t=

M

3RT

πd

2

N/V

1

;t=

T

CV

where C=

πd

2

B

3R

M

⇒T∝

t

2

V

2

For adiabatic

TV

γ−1

=k

t

2

V

2

V

γ−1

=k

t

2

V

γ−1

=k, t∝

2

γ+1

so q=

2

γ+1

Explanation:

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