Question

if value of 8power x+1 = 64 what is the value of 3 power 2x +1​

Answer 1

expression is 27.

Step-by-step explanation:

It has been given that

8^{x+1}=648

x+1

=64

Take log both sides

\log(8^{x+1})=\log64log(8

x+1

)=log64

Apply the log rule \log x^y=y\log xlogx

y

=ylogx

(x+1)\log8)=\log64(x+1)log8)=log64

Divide both sides by log 8

\begin{gathered}x+1=\frac{\log64}{\log8}\\\\x+1=\frac{\log8^2}{\log8}\\\\x+1=\frac{2\log8}{\log8}\\\\x+1=2\\\\x=1\end{gathered}

x+1=

log8

log64

x+1=

log8

log8

2

x+1=

log8

2log8

x+1=2

x=1

Now, we have to find the value of the expression

3^{2x+1}3

2x+1

Substitute x = 1

\begin{gathered}3^{2\cdot1+1}\\\\=3^{2+1}\\\\=3^3\\\\=27\end{gathered}

3

2⋅1+1

=3

2+1

=3

3

=27

Answer 2

Answer:

27

Step-by-step explanation:

${8}^{x + 1} \: = 64 \\ {8}^{x + 1} = {8}^{2} \\ bases \: are \: equal \: so \: bases \: would \: \: cut \\ x + 1 = 2 \\ x = 1 \\ \\ {3}^{2x + 1} = {3}^{2 \times 1 + 1} \\ {3}^{3} \\ 27$