Question

if value of determinant 3√6 –4√2
5√3 x

is 26√6 , find the value ​

Answer 1

$\bold{given}$

$| \sqrt[3]{6} \: \: \: \: \: - \sqrt[4]{2 \: } \: | = \sqrt[26]{6}$

$\sqrt[5]{3} \: \: \: x \: = \sqrt[26]{6}$

$\bold{to \: find}$

$the \: value \: of \: x \:$

$consider$

$| \sqrt[3]{6} \: \: - 4 \sqrt{2} | \\ | \sqrt[5]{3} \: \: \: \: \: \: \: \: \: \: \: \: \: x\: \: \: | = \sqrt[26]{6}$

$expanding \: we \: get$

$3x \sqrt{6} + 20 \sqrt{6}$

$\to \: 3x \sqrt{6 } = 26 \sqrt{6} - 26 \sqrt{6}$

$\to \: 3x \sqrt{6} = 6\sqrt{6}$

$\to \: 3x = 6$

$\to \boxed{x = 2}$

$\therefore \bold{the \: value \: of \: x \: is \: 2}$

Find more:

The sum of the real roots of the equation | x 6 1 |

| 2 3x (x - 3)| = 0 | 3 2x (x = 2)|

is equal to (A) -4 (B) 0

hope it helps you