Question

IF VALUE OF QUADRATIC POLYNOMIAL P(X) IS 0 AND VALUE OF P(-2)=2 VALUE OF P(2) IS

Answer 1

Answer:

Since the quadratic polynomial p(x) = 0 at only at -1, p(x) has a double zero at -1. Therefore, p(x) can be taken as a(x+1)^2. Given p(-2) = 2 => a(-2+1)^2 = 2 or a = 2.

Step-by-step explanation:

Answer 2

Hola mate

Here is you answer -

Consider the quadratic equation as:

p(x) = x² - bx + c = 0

at x=(-1), p(x) = 0, that is p(-1) = 0

p(-1) = (-1)² - b(-1) + c = 0

1 + b + c = 0 __________(1)

p(-2) = (-2)² - b(-2) + c = 0

4 + 2b + c =0 _________(2)

Now, Solve these 2 equation

from equation (1):

c = -(b +1)

put this "c" in equation (2):

4 + 2b + (-(b +1)) = 0

4 + 2b - b - 1 = 0

4 + b - 1 = 0

b = -3

and c = -(-3 + 1) = -(-2) = 2

So the quadratic equation is:

x² - (-3)x + 2 = 0

x² + 3x + 2 = 0

Hope it helps you!