if values of ΔH°f of ICL , Cl and I are respectively 17.57 , 121.34 , 106.96 j/mol . The values of I-Cl (bond energy ) in j/mol is
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210.73 J mol⁻¹ is the Bond energy of I-Cl.
step by step explanation:
The Reaction between I₂ and Cl₂ is given by ₂₂⇄
Therefore taking the enthalpy of formation values into consideration,
given ΔH=17.57 J/mol; ΔH=121.34 J/mol and ΔH=106.96 J/m
The bond dissociation energy of ΔH+ΔH-ΔH------(1)
⇒Bond energy of =
since given enthalpy of formation is for single atoms in gaseous form not molecular enthalpy, we can directly substitute them in equation(1) and obtain this answer else we have to convert them into gaseous enthalpies from molecular enthalpies.
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