Question

If variance of Binomial distribution is 2, n=9, then p is

Answer 1

x: The number of successes that result from the binomial experiment. n: The number of trials in the binomial experiment. P: The probability of success on an individual trial. Q: The probability of failure on an individual trial. (This is equal to 1 - P.)

Answer 2

Answer:

Step-by-step explanation:

The mean is 4 and the variance is 3.

For a binomial random variable X, E(X) = np and var(X) = npq, where n is the number of trials, p is the probability of success and q is the probability of failure.

So, we have np = 4 … (i) and npq = 3 …(ii)

Dividing the LHS and RHS of equation (ii) by equation (i) we have

npq/np = 3/4

=> q = 3/4

Therefore, we have p = 1 - q = 1 - 3/4 = 1/4

Substituting the value of p = 1/4 in equation (i), we have n = 16.

So, the probability of obtaining 5 successes = 16C5[(1/4)^5][(3/4)^11]

Hope it helps

:)