If Vase I contain 02 white and 4 Black balls and Vase II contain 04 White and 4 black balls if a ball is drawn out of random from one of the two vase what is probability that it was a white ball
Answers
Answered by
3
In vase 1 the probability of getting a white ball = 2/6 =1/3
In vase 2 the probability of getting a white ball = 4/8 = 1/2
Hope it helps you...✌️☺️❤️
Answered by
14
the probability of first one will be
no.of white balls / total no. of balls
i.e. 2/6=1/3
the probability of second one will be:
no. of white balls / total no. of balls
i.e. 4/8
=1/2
total probability :
no.of white balls / total no. of balls
i.e. 6/14
=3/7
Similar questions