Question

If vector 2i+3j-6k ,6i-2j+3k are two consecutive sides of a triangle then the perimeter of triangle is

Answer 1

Step-by-step explanation:

Given If vector 2i+3j-6k ,6i-2j+3k are two consecutive sides of a triangle then the perimeter of triangle is

• Now we have
• Vector PQ = 2 I + 3 j – 6 k
• Vector QR = 6 I – 2 j + 3 k  
• So PQ + QR = PR
• So PR = (2 I + 3 j – 6 k) + (6 I – 2 j + 3 k)
•           = 8 I + j – 3k
• Now PQ = l PQ l = √2^2 + 3^2 + (- 6)^2  
•                             = √49
•                              = 7 units
• Also l QR l = √6^2 + (- 2)^2 + 3^2
•                    = √49
•                    = 7 units
• So PR = √8^2 + 1^2 + (- 3)^2
•            = √74 units
• Now perimeter = PQ + QR + PR

                            = √74 + 14 units

Reference link will be

https://brainly.in/question/2865576

https://brainly.in/question/5314643