if vector a =3unit due east and vactor b =4unit due 60 degree North of West then find Vector a +vector
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Let the two vectors be P and Q and their resultant vector be R.
Let the angle between P and Q be θ.
Given: ∣P∣=3, ∣Q∣=4 and ∣R∣=5 units
Magnitude of resultant vector ∣R∣
2
=∣P∣
2
+∣Q∣
2
+2∣P∣∣Q∣cosθ
∴ 5
2
=3
2
+4
2
+2(3)(4)cosθ
We get cosθ=0
⟹θ=90
o
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