If (vector) |A|=7 and (vector) |B|=11 and (vector) |A+B|=8, then what is |A-B| equal to?
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If (vector) |A|=7 and (vector) |B|=11 and (vector) |A+B|=8, then what is |A-B| equal to?
Assuming that the vector that is being referred to is 2-dimensional:
Let A=ax+by , B=cx+dy
∴A+B=(a+c)x+(b+d)y
And A−B=(a−c)x+(b−d)y
Where the vectors x and y are orthogonal unit vectors
|A|=a2+b2−−−−−−√=7
|A|2=a2+b2=49
|B|=c2+d2−−−−−−√=11
|B|2=c2+d2=121
|A+B|=a2+c2+2ac+b2+d2+2bc−−−−−−−−−−−−−−−−−−−−−−−√
=48+2ac+121+2bd−−−−−−−−−−−−−−−−−√=170+2ac+2bd−−−−−−−−−−−−−√=8
∴2(ac+bd)=64−170=−106
So using this we can use a similar method for A−B :
|A−B|=a2+c2−2ac+b2+d2−2bd−−−−−−−−−−−−−−−−−−−−−−−√
=170−2(ac+bd)−−−−−−−−−−−−−√=170−(−106)−−−−−−−−−−−√=276−−−√=269−−√
or in decimal form ≈16.61
Explanation:
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