if vector a and b are two vectors such that Ia+bI=a then prove that vector 2a+b is perpendicular to vector b. pls help..
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Explanation:
( A+B)•A= 0
|A|^2+B• A=0
B•A=-|A|^2
|A+B|=|A|
|A|^2+|B|^2+2A•B =|A|^2
|A|^2|B|^2-2|A|^2=|A|^2
|B|^2=|A|^2
|B|=Sqrt 2|A|
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