if vector A=coswt i^ + sinwt j^ and vector B= Cos(wt/2) i^ + sin(wt/2)j^ are functions of time,then the value of t at which they are orthogonal to each other is?
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Answered by
46
If A vector and B vector are orthogonal then the angle between them will be 90.
Thus the resultant time =>
T = √( A^2 + B^2 + 2AB×cos¢)
= √{ (cos^2wt + sin^2wt) + (cos^2(wt/2) + sin^2(wt/2)) + 0 }
= √(1 + 1)
= √2
T = √2...●
●●●●●●●●●●●●●●●●●
Hope it was helpful.
Thus the resultant time =>
T = √( A^2 + B^2 + 2AB×cos¢)
= √{ (cos^2wt + sin^2wt) + (cos^2(wt/2) + sin^2(wt/2)) + 0 }
= √(1 + 1)
= √2
T = √2...●
●●●●●●●●●●●●●●●●●
Hope it was helpful.
SidVK:
Main vector ke multply ki baat nhi krra addition ki baat kar raha hun..addition me resulting vector hota hai...jise R se denote krte hain..shaq hai to open the book..
maine kb bola ki ye galat hai
mai to bol rha hun ki "resulting time" aisa koi word nhi exist karta
Aap hi bol rhe ki aisa kuchh nhi hota resulting vector hota hi nhi
Haan par time ki baat ho rhi...vector time ka hai to resulting vector bhi resulting time hi hoga..
nhi bhai
In which class you are?
12th
you should revise vector once time.
I agree with atul
Answered by
258
Answer: Option-4(^\w)
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