Question

if vector a = i - 2j + k and vector b = 4i - 3j - 4k and theeta is the angle between them, then prove that cos theeta root 6 / root 41​

Answer 1

Step-by-step explanation:

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Answer 2

Given that : A = i-2j+k and B = 4i-3j-4k

|A| = √(1)²+(-2)²+(1)² = √6

|B| = √(4)²+(-3)²+(-4)² = √16+9+16 = √41

A.B = (i-2j+k).(4i-3j-4k)

=> A.B = 4+6-4 =6

Now, cosA = A.B/|A|.|B|

=> cosA = 6/√6.√41 = √6/√41

HENCE PROVED ✔️✔️

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