if vector A=vector B+vector C
and the magnitude of vector A, vector B, Vector C are5,4and3 units respectively. then find the angle between vector A and vector C is
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IVector AI= A
A²= B + C + 2BCCosΘ
25 = 4 + 3 + 24CosO
24CosO= 18
CosO= 18/24
CosO= 3/4
O=40°
Angle between B ,C = 40Degrees
Tan∅ = BSin40/B+CCos40
=4x0.74/4 + 3x0.74
=2.96/4+ 2.22
=2.96/6.22
=0.47
∅=25.2
Brainliest answer pls..
A²= B + C + 2BCCosΘ
25 = 4 + 3 + 24CosO
24CosO= 18
CosO= 18/24
CosO= 3/4
O=40°
Angle between B ,C = 40Degrees
Tan∅ = BSin40/B+CCos40
=4x0.74/4 + 3x0.74
=2.96/4+ 2.22
=2.96/6.22
=0.47
∅=25.2
Brainliest answer pls..
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