Question

if vector AB=2i^-j^+k^ and vector OB=3i^-4j^+4k^ find position vector OA​

Answer 1

The position vector OA is i^ - 3j^ + 3k^.  

Given:

Two vectors AB = 2i^ - j^ + k^ and OB = 3i^ - 4j^ + 4k^

To Find:

We need to find the position vector OA

Solution:

The position vector OA can be calculated as follows-

AB = OB - OA

OA = OB - AB

Substituting the values in the equation, we get-

OA = 3i^ - 4j^ + 4k^ - (2i^ - j^ + k^)

OA = 3i^ - 4j^ + 4k^ - 2i^ + j^ - k^

OA = 3i^ - 2i^ - 4j^ + j^ + 4k^ - k^

OA = i^ - 3j^ + 3k^

Thus, the position vector OA is i^ - 3j^ + 3k^.  

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