if vector IaI=8 and vector IbI=3 and Ia×bI=12, find the angle between vector a and b. please help me solve this question.
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Answer:
30 degree
Explanation:
a=8
b=3
a cross b=12
according to cross product rule
a cross b = absin0
12=8*3sintheta
12=24sintheta
0.5=sintheta
theta=30 degree
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