if vector P, vector q and vector R are represented in a diagram prove that vector P + vector R = vector 2q
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The angle between will be 0°.
If resultant is P-Q, then angle would be 180°
Formula is R² = P² + Q² - 2PQCos(theta)
R is resultant; theta is angle between P & Q; R,P,Q are in Mod value.
(P+Q)² = P² + Q² - 2PQCos(theta)
P² + Q² + 2PQ = P² + Q² - 2PQCos(theta)
2PQ = 2PQCos(theta)
Cos(theta) = 1
Cos(theta) = Cos0°
theta = 0
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