if vector r = 2.0t^2 i cap - 4.0 t j cap. find the magnitude of velocity at t =2.
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Answer:
(a)
v(t)=dr/dt
=3.0i^−4.0tj^
a(t)=dv(t)/dt
=−4.0j^
(b)
v(2)=3.0i^−8.0j^
v(2)=8.54m/s
∠v(2)=tan−1(−8/3)=−69.44∘with x axis
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