if vector R = vector P × vector Q, show that vector 4R . (vector 3P + vector 6Q) = 0
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Answer:
DONE.
Explanation:
R = P×Q (R is perpendicular to P and Q )
4R.( 3P+ 6Q) = 4R.3P+ 4R.6Q ( R is perpendicular to P and Q therefore their dot product will be 0 as cos 90 is 0)
hence 4R.3P= 0
4R.6Q= 0
SO, 4R.( 3P+ 6Q) = 4R.3P+ 4R.6Q= 0
HENCE PROVED
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