Question

If vectorA+ vectorB = vectorC and A-B=C then find the angle between A and B​

Answer 1

Answer:

180

Explanation:

X=vector a

Y=vector b

Z=vector c

a=x

b=y

c=z

X+Y=Z

y=x-z

X+(X-Z) =Z

SQUARING ON BOTH SIDES

${x}^{2} + {x }^{2} + y ^{2} + 2xy \cos(xy )= z ^{2}$

Vector square magnitude is 1

1+1+1+2cos(xy) =1

3+2cos(xy)=1

2cos(xy)=-2

Cos(xy)=-1

Angle between them is 180